经典面试题解答

来源:未知作者:操作系统 日期:2020/01/31 19:17 浏览:

ListMapString,ObjectmasterList=aa.query();//size=3ListMapString,ObjectdetailList=bb.query();//size=10for(inti=0;imasterList.size(State of Qatar;i++卡塔尔国{Stringtest01=masterList.get(iState of Qatar.get("test01"卡塔尔国.toString(State of Qatar;for(intj=0;jdetailList.size(卡塔尔(قطر‎;j++卡塔尔(قطر‎{Stringtest02=detailList.get(j卡塔尔(قطر‎.get("test02"State of Qatar.toString(卡塔尔;if(test01.equals(test02卡塔尔卡塔尔(قطر‎{System.out.println("值万分"卡塔尔国;//出发点是:多个值特别时就将它从detailList里消亡掉//丰盛下边那句后,就跳出循环了,detailList.remove(j);}}}

举例 当前您的U福特ExplorerL是: //www.jb51.net/index.php?test=1&kk=2 少年老成旦想博得test,则能够引进插件后, 用如下方法赢得: var test = $.query.get; 借使参数有三个同样的名称 ,则能够这么: var arr = $.query.get; 输出: [ 值1 , 值2, 值3...] 假设要博得三个类似名称中的某一个,能够这么: var arrayElement = $.query.get; 此插件不仅可以得到参数,也能安装参数。 设置贰个参数: var newUrl = $.query.set.toString(State of Qatar; 输出 : "?section=5" 设置五个参数: var newUrl = $.query.set.set.toString(卡塔尔; 输出 : "?action=do§ion=5" 删除一个参数: var oldQueryAgain = $.query.REMOVE; 清空全数参数: var emptyQuery = $.query.empty(State of Qatar; 复制全部参数: var stillTheSame = $.query.copy(卡塔尔国; 插件地址: javascript[js]得到url参数的代码JavaScript U奥迪Q5L参数读取改革版

public class TestList2 { //用1、2、2、3、4、5那八个数字,用java写三个main函数,打字与印刷出装有分化的排列,如:512234、412345等,供给:"4"不可能在第几人,"3"与"5"不财富源。 public static void main(String[] args) { List<String> l = new ArrayList<String>(); l.add("1");l.add("2");l.add("2");l.add("3");l.add("4");l.add("5"); List<String> l1 = new ArrayList<String>(); List<String> l2 = new ArrayList<String>(); List<String> l3 = new ArrayList<String>(); List<String> l4 = new ArrayList<String>(); List<String> l5 = new ArrayList<String>(); List<String> rel = new ArrayList<String>(); StringBuilder sb = new StringBuilder(); for (int i = 0; i < l.size(); i++) { sb.append(l.get(i)); String n1 = l.remove(i); l1 = l; for (int j = 0; j < l1.size(); j++) { sb.append(l1.get(j)); String n2 = l1.remove(j); l2 = l1; for (int j2 = 0; j2 < l2.size(); j2++) { sb.append(l2.get(j2)); String n3 = l2.remove(j2); l3 = l2; for (int k = 0; k < l3.size(); k++) { sb.append(l3.get(k)); String n4 = l3.remove(k); l4 = l3; for (int k2 = 0; k2 < l4.size(); k2++) { sb.append(l4.get(k2)); String n5 = l4.remove(k2); l5 = l4; for (int m = 0; m < l5.size(); m++) { sb.append(l.get(m)); String n6 = l5.remove(m); System.out.println(sb.toString()); if (!rel.contains(sb.toString()) && sb.toString().indexOf("4")!=2 && !sb.toString().contains("35") && !sb.toString().contains("53")) { rel.add(sb.toString()); } sb.delete(sb.length()-1, sb.length()); l5.add(m, n6); } sb.delete(sb.length()-1, sb.length()); l4.add(k2, n5); } sb.delete(sb.length()-1, sb.length()); l3.add(k, n4); } sb.delete(sb.length()-1, sb.length()); l2.add(j2, n3); } sb.delete(sb.length()-1, sb.length()); l1.add(j, n2); } sb.delete(sb.length()-1, sb.length()); l.add(i, n1); } System.out.println(rel.size()); System.out.println(rel.toString()); }

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